mg and mcg dosages and dilution question


Status
Not open for further replies.

Dream Merchant

Moderator
Staff member
Jan 11, 2007
9,660
6
38
#1
I know this is a photography forum, but I know there are a lot of really knowledgeable people here that might be able to help, and I was hoping to clarify something.


OBJECTIVE: To get 78mcg of X in working solution that's easy to measure accurately

The stock strength of the supplied component is: 10mg/ml or 1ml = 10,000 mcg. Is that correct?



To get 78mcg, I'll need:

1ml / 10,000 x 78 = 0.0078ml of X

To draw 0.0078ml accurately is not possible, and the margin of error is too great.



If I take 1 ml of X (10,000mcg) and add 100ml of water, I will be diluting it to the power of 100x.

So now I have 101ml of working solution which contains 10,000 mcg of X.



If I want 78 mcg of X, I draw

101ml / 10,000 x 78 = 0.7878ml of the working solution.


Is that correct?



My allowed margin of error is speced at 10x the recommended dosage NAD and >16x with possible adverse reactions, but I really want to get it as accurately as possible.
 

Last edited:

giantcanopy

Senior Member
Feb 11, 2007
6,232
2
0
SG
#2
I If I take 1 ml of X (10,000mcg) and add 100ml of water, I will be diluting it to the power of 100x.

So now I have 101ml of working solution which contains 10,000 mcg of X
Chris you can add 99mls of water to the 1 ml to make up a dilution of 100 to simplify and draw 0.78mls at the end.

ryan
 

Dream Merchant

Moderator
Staff member
Jan 11, 2007
9,660
6
38
#3
Thanks Ryan! :)

I wanted to make sure I got that right, considering the margins involved.

CHEERS!
 

Status
Not open for further replies.
Top Bottom