1. Math Probabilities Qn

need to enlist the aid of those who still can remmeber probabilities....i returned all to the teacher years ago :P

anyway the qn is, if i throw three dice, whats the probability that at least ONE of them will show a certain number that i picked. e.g. i pick number 6. whats the probability that at least ONE of them will show a 6?

b) how about 2 of them?

hope to get some answers! cheers!

a) 1/6+1/6+1/6 = 1/2

taking b to mean three dice thrown, two giving the same number selected.
b) 1/6*1/6+1/6*1/6+1/6*1/6 = 1/12

might be a bit wrong though due to some overlap.

3. try again:

b) 1/6*1/6*5/6+1/6*1/6*5/6+1/6*1/6*5/6+1/6*1/6*1/6=0.074074

a) 1/6*5/6*5/6+1/6*5/6*5/6+1/6*5/6*5/6+ b = 0.4213

4. hehe i initially thot the answer was 1/2 also in (a). but i realised that it can't be, cos if using that working, throwing 6 dice gives a probability of 1 to get the number

Originally Posted by mpenza
a) 1/6+1/6+1/6 = 1/2

taking b to mean three dice thrown, two giving the same number selected.
b) 1/6*1/6+1/6*1/6+1/6*1/6 = 1/12

might be a bit wrong though due to some overlap.

5. Use counting methods instead of probability. Sure correct one.

3 dice gives 6x6x6 = 216 possible combinations (use a spreadsheet if you need). Out of these 216, 91 combinations contain the number 6. Therefore, the answer is 91/216.

1/2 is the wrong answer bcoz it does not take overlapping solutions into account.

6. wah how did you figure that out so fast? :P how u get the ez way to come up with all the combos?

Originally Posted by ST1100
Use counting methods instead of probability. Sure correct one.

3 dice gives 6x6x6 = 216 possible combinations (use a spreadsheet if you need). Out of these 216, 91 combinations contain the number 6. Therefore, the answer is 96/216.

1/2 is the wrong answer bcoz it does not take overlapping solutions into account.

7. Originally Posted by ST1100
Use counting methods instead of probability. Sure correct one.

3 dice gives 6x6x6 = 216 possible combinations (use a spreadsheet if you need). Out of these 216, 91 combinations contain the number 6. Therefore, the answer is 96/216.

1/2 is the wrong answer bcoz it does not take overlapping solutions into account.
same answer as mine yup, working out the combinations is a sure way to get the answer but it might be quite tedious for cases which have a lot more combinations.

8. Originally Posted by vince123123
wah how did you figure that out so fast? :P how u get the ez way to come up with all the combos?
Erm, i did it mentally, but for 2 or more numbers, i would use a spreadsheet:

1 1 1
1 1 2
1 1 3
1 1 4
...
...
6 6 3
6 6 4
6 6 5
6 6 6

If you know some excel programming, you can get excel to do the counting for you too.

(Actually, i'm still trying to think of a correct way to calculate this using probablity instead of counting.)

9. Ok, the way to do it with probabilities:

There is a 5/6 chance that there is no 6 on the first dice, and 5/6 chance on the second and third. Therefore, the answer is 1-(5/6^3).

10. wah not bad, so far there are 3 diff workings and all get hte same answer

thanks guys!

11. this is a faster than what I've calculated

12. wahh.. probability.. did that last time ... for statistics classes...

13. Well done! As an ex-Statistics major, for a while I did not know how and where to start!

Well done! As an ex-Statistics major, for a while I did not know how and where to start!
tsk tsk. hahah, return all to teacher liao ar?

15. damn...where's my maths....

16. Originally Posted by simplicity_
tsk tsk. hahah, return all to teacher liao ar?
No ... I am a teacher who has lost it!

No ... I am a teacher who has lost it!
even worst...

heehee..

Btw... you graduated with a degree in statistics?

No ... I am a teacher who has lost it!
hahaha..

haiyoh.. jia lat leh, liddat.

19. visualise a tree diagram,...each die giving off to 6 branches, it'll be easy.

ST1100's answer using P(an event) = 1 - P(all other events) = 1-(5/6^3) is the quickest.

20. BTW, the answer for picking two numbers is 1-(4/6 ^3).

Generic formula is 1-((6-r)/6 ^ d), where r is the number of picks and d the number of dice.

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