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Thread: Maths question

  1. #21
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    Join Date
    Jul 2003
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    Singapore, North Area
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    507

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    Sorry.... forget to change that...


  2. #22

    Default

    Thanks all for the help

  3. #23
    Member
    Join Date
    Feb 2003
    Location
    Singapore
    Posts
    56

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    my solution...

    6 men can do the job in 96 hours, therefore 1 man can do it in 6x96=576 hours

    9 women can do the same job in 166.2 hours, therefore 1 woman can do it in 9x166.2=1495.8 hours

    1/576 --> the fraction of the job that 1 man can do in 1 hour

    2 x (1/576) --> the fraction of the job that 2 men can do in 1 hour

    1/1495.8 -- the fraction of the job that 1 woman can do in 1 hour

    4 x (1/1495.8) --> the fraction of the job that 4 women can do in 1 hour


    if h is the total hours that will take 2 men and 4 women to do the job,
    then 1/h is the fraction of the job that it will be done by 2-men and 4-women in 1 hour


    therefore,

    ....2/576.............+....4/1495.8.............=.....1/h

    ....work by 2 men.......work by 4 women.........job done
    ....in 1 hour...............in 1 hour.....................in 1 hour


    simpifying,

    2(1495.8)h + 4(576)h = 576(1495.8)

    2991.6h + 2304h = 861580.8

    5295.6h = 861580.8

    solving for h, qed

    h = 162.69


    hope this helps...
    Last edited by licorx; 27th September 2003 at 05:41 PM.

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