![]() |
|
|||||||
| General, Reviews, Tech Talk Share tips & tricks, techniques, general photography chat. |
|
|
|
|
Thread Tools |
|
|
#1 |
|
Moderator
Join Date: Jan 2002
Location: New York City
Posts: 13,397
|
Say I take a 1s shot using F1.8. How many seconds would it take for a F3.2 lens to get the same level of exposure? Are there any formula I could use?
|
|
|
|
|
#2 |
|
Senior Member
Join Date: Jan 2002
Location: UK
Posts: 3,081
|
I'm sure there's a complex mathematical formula somewhere, but use the following table until someone coughs it up:
f1.4 -- f1.6 -- f1.8 f2.0 f2.8 -- f3.2 -- f3.5 f4 Each figure on the left column is a full f-stop, while the indicated figures on the right at the universally accepted (for convenience) 1/3 stops. So f1.8 is 1 and 2/3 stop faster than f3.2, hence you should use that amount a lengthier shutter speed, or 3s. Last edited by Jed; 20th January 2002 at 03:31 AM. |
|
|
|
|
#3 |
|
Senior Member
Join Date: Jan 2002
Posts: 2,262
|
f/3.6 will be 2 stops faster than f/1.8, so f/3.2 will be slightly less than 2s?
|
|
|
| Sponsored Link |
|
|
#4 |
|
Senior Member
Join Date: Jan 2002
Location: UK
Posts: 3,081
|
No, two stops away from 1s is 4s (1s, 2s, 4s, 8s, etc.) So it's slightly less than 4s.
|
|
|
|
|
#5 |
|
Moderator
Join Date: Jan 2002
Location: New York City
Posts: 13,397
|
Thanks guys for enlightening me!
![]() So, roughly every "1.414" times is one stop loss in light requiring doubling of the exposure time right? |
|
|
|
|
#6 |
|
Senior Member
Join Date: Jan 2002
Location: UK
Posts: 3,081
|
Yes that's right. Cause apertures are measured as a reciprocal ratio of the diameter, area wise. Hence the number is achieved by a root of two, which is 1.414 etc as you point out.
|
|
|
![]() |
| Bookmarks |
| Thread Tools | |
|