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Thread: Try this for fun

  1. #1
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    Default Try this for fun

    Try this for the fun of it.

    Anyone knows the answer?

  2. #2

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    18

  3. #3

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    Hrm...wait...no...

    lost...

  4. #4

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    haha this game got me quite a while....finally got it...

  5. #5
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    noticed that the symbols accompanying the numbers keep changing. but still dont know why

  6. #6

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    Wahhhh!!!! So scary!!! How does it know??!!

  7. #7

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    what is the secret??
    my flickr account

  8. #8
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    Keep it running for a few days, will reveal it later.

  9. #9

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    The answer will always be the symbol associated with the multiples of 9 (which are all the same symbols)!

  10. #10

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    Originally posted by SzennyBoy
    The answer will always be the symbol associated with the multiples of 9 (which are all the same symbols)!


    You know about it! I've just completed 9, 18, 27 only.

  11. #11
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    can some mathematician explain why a 2 digit number - the sum of the 2 digits will result in a number that is a multiple of 9. 10s.

  12. #12
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    figured it out liao, but only after i know the result ...

  13. #13

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    aaargh got this in a mail some time ago. but i figured out how it works. well heres the spoiler. according to the law of mathematics. its seems that any 2 digit numbered thats has its numebers added then subtracted from the orginal number will always be a multiple of 9. Sooooo if u notice all the multiples of 9 have the same symbol. so there u have it. No it cannot read our mind

  14. #14
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    OK. Here's some algebra:

    For the 2-digit number that you pick, let "a" be the most significant digit and "b" be the least significant digit, thus 1<=a<=9 and 0<=b<=9.

    "a" cannot be 0 or else it will not be a 2-digit number anymore.

    Then the 2-digit number has a value of 10a + b
    The sum of the 2 digits is a + b

    Subtract the sum of the 2 digits from the original 2-digit number, and the result is (10a + b) - (a + b) = 9a.

    Since "a" is an integer from 1 to 9, then the result is always a multiple of 9 (from 1x9=9 to 9x9=81), no matter which 2-digit number you pick at the beginning.

    So, the trick is to assign the same symbol to all multiples of 9 from 9 to 81, and always show that symbol in the crystal ball. even though 90 and 99 are also multiples of 9, they will not be the results because the limit is 9x9 = 81. So the symbols for 90 and 99 can be different.

    - Roy
    As complexity rises, precise statements lose meaning and meaningful statements lose precision.

  15. #15
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    roygoh, you sure knows your sums well.

  16. #16
    Sin
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    Originally posted by roygoh
    OK. Here's some algebra:

    For the 2-digit number that you pick, let "a" be the most significant digit and "b" be the least significant digit, thus 1<=a<=9 and 0<=b<=9.

    "a" cannot be 0 or else it will not be a 2-digit number anymore.

    Then the 2-digit number has a value of 10a + b
    The sum of the 2 digits is a + b

    Subtract the sum of the 2 digits from the original 2-digit number, and the result is (10a + b) - (a + b) = 9a.

    Since "a" is an integer from 1 to 9, then the result is always a multiple of 9 (from 1x9=9 to 9x9=81), no matter which 2-digit number you pick at the beginning.

    So, the trick is to assign the same symbol to all multiples of 9 from 9 to 81, and always show that symbol in the crystal ball. even though 90 and 99 are also multiples of 9, they will not be the results because the limit is 9x9 = 81. So the symbols for 90 and 99 can be different.

    - Roy
    I go down on my knees and say:
    "I'm not worthy! I'm not worthy!"

  17. #17
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    Originally posted by Goondu
    roygoh, you sure knows your sums well.
    Originally posted by Sin
    I go down on my knees and say:
    "I'm not worthy! I'm not worthy!"
    paiseh...paiseh...
    As complexity rises, precise statements lose meaning and meaningful statements lose precision.

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