Recently my beach photos were coming out a bit washed out cos I didn't exp compensate up a stop or 2 for the reflection from the sand. My next trip I plan to do this plus also bring along my circular polarising filter.
Anyone good with physics? From my memory of physics lessons long long ago, a large source of light at the beach is light that is reflected from the sand. Polarising filters alter this by causing light waves to travel in a single plane only, which has the additional effect of reducing intensity, thats why they tend to reduce light a stop or 2 if i'm not wrong.
So the problem is that at the beach lets say I want to polarise and make my skies bluer and cut down water reflection. Do I still need to exposure compensate up for reflection from the sand? This keeping in mind that the "rotation" of the polariser to cut off water reflection etc. may not be the same plane by which the light coming of the sand is?
Or since the polarising filter already cuts off light intensity (sometimes I have to exp compensate up with it) I can just use my metered value?
I vaguely remember something in physics that says most waves striking the horizontal surface (incl sand and sea) reflect in the same plane (vertical i think). My physics not too good as you can see. In that case the plane by which I have no water reflection would be the same plane where I cut off sand reflection.